5^2 + 12^2 = c^2
25 + 144 = c^2
169 = c^2
take the square root of both sides
+ - 13 = c
-x - y = 8
2x - y = -1
Ok, we are going to solve this in 2 parts. First we have to solve for one of the variables in one of the equation in terms of the other variable. I like to take the easiest equation first and try to avoid fractions, so let's use the first equation and solve for x.
-x - y = 8 add y to each side
-x = 8 + y divide by -1
x = -8 - y
So now we have a value for x in terms of y that we can use to substitute into the other equation. In the other equation we are going to put -8 - y in place of the x.
2x - y = -1
2(-8 - y) - y = -1 multiply the 2 through the parentheses
-16 - 2y - y = -1 combine like terms
-16 - 3y = -1 add 16 to both sides
-3y = 15 divide each side by -3
y = -5
Now we have a value for y. We need to plug it into either of the original equations then solve for x. I usually choose the most simple equation.
-x - y = 8
-x - (-5) = 8 multiply -1 through the parentheses
-x + 5 = 8 subtract 5 from each side
-x = 3 divide each side by -1
x = -3
So our solution set is
(-3, -5)
That is the point on the grid where the 2 equations are equal, so that is the place where they intersect.
Angle 4 and Angle 2 are vertical angles, meaning that they are congruent. Therefore, the measure of angle 2 is 127 degrees.
Angle 4 and Angle 3 are a linear pair, meaning that they are supplementary and add up to 180 degrees. Therefore, the measure of angle 3 is 53 degrees.
Angle 3 and Angle 1 are vertical angles, meaning that they are congruent. Therefore, the measure of angle 1 is 53 degrees.
Hope this helps!
Answer:
FOR LEMON = 1/10
FOR RAISIN = 4/9
Step-by-step explanation:
Part A:
The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

Part B:
</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and
standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:
</span>