Answer:
The largest possible number of x intercept is 9 while the largest possible number of relative max/min is 8
Step-by-step explanation:
For any polynomial of degree n with distinct and real solutions, it can have at most n different x intercepts. This would imply it can have at most 9 distinct real solutions.
It can also have at most n-1 relative max/min in alternating order. This is best illustrated when such polynomial is sketched on a graph.
For example a quadratic expression is a polynomial of degree 2 and has at most 2 distinct solutions and 1 relative max/min.
In this question, for the polynomial, its degree (n) = 9
So it can have at most 9 x intercepts and at most 8 relative max/min.
Answer: A
Step-by-step explanation:
Just took the test
Answer:
112 divided by 4 is 28. So 16 times 4 = 64. 64 divided by 5 is 12. 12 apples per 8 pounds. so 12 times 4 is 48 so your answer is 48
Step-by-step explanation:
If this pertains to the Pythagorean theorem, then the answer that you would most likely to end up with is by utilizing the equation a² + b² = c² where a and b are the legs of the triangle and c is the hypotenuse. The hypotenuse refer to the longest side of the triangle while the other two would be the legs of the triangle.
When solving for the missing length, just substitute the values given to their respective places in the equation. If a length of a leg is missing, then substitute the other leg's value to either a or b, then substitute the length of the hypotenuse to c. Then solve. Solving for the hypotenuse's length would be a lot easier than the legs.
Answer:
x=6 . m<PQS=82 m<SQR=61 :)
Step-by-step explanation:
(13x+4) + (10x-1) = 141
combine like terms
23x+3=141
subtract 3 from both sides
23x=138
divide both sides by 23
x=6
substitute x into both original equations
m<PQS=13(6)+4
m<PQS=78+4
m<PQS= 82
m<SQR=10(6)+1
m<SQR=60+1
M<SQR=61