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pav-90 [236]
3 years ago
14

The table shows the annual increase in cost in t years for certain grocery items. Based on the formula A = C(1 + r)t, which equa

tion could you use to determine the cost in t years for a loaf of bread?
A)A = 3.60t(1.05)Eliminate

B)A = 3.60(0.95)t

C)A = 3.60(1.05)t

D)A = 3.60(0.05)t
Mathematics
2 answers:
jek_recluse [69]3 years ago
7 0
C is the answer to your question
lara [203]3 years ago
7 0

Answer:

Option C

Step-by-step explanation:

Given that there is an annual increase in cost

If rate of increase is r then we have

C(1+r) for I year and for II year C(1+r)^2 etc

Hence for t years

A = C(1 + r)^t

Option A is wrong because exponent t should be for 1.05

Option B is wrong because here 1-r is done instead of 1+4

Option C is correct because r =0.05 and C=3.60 is correctly substituted

Option D is wrong because 1 is not added to r

SO finally only option C is right

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Which expression is equivalent to 24 + 20​
Maslowich
24+20=44
4(6+5)=44
the first one
8 0
3 years ago
Because of a virus introduced into a bacterial culture, the population of the bacteria decreasedfrom 3000 to 1000 in 50 minutes.
Mamont248 [21]

Answer:

208

Step-by-step explanation:

Given that;

Given that;

y= a(1 - b)^t

Where;

wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.

To obtain the constant b,

y= ae^-bt

Substituting values;

1000 = 3000 e^-b(50)

1000/3000 = e^b(50)

0.33 = e^b-(50)

ln (0.33) = ln(e^b(-50))

-1.1 = -50b

b= 1.1/50

b= 0.022

After two hours or 120 minutes;

y= 3000(1 - 0.022)^120

y= 207.8661772

y= 208

8 0
2 years ago
Given f(x)=4X+9, find the equation for f^-1(x)
Ilia_Sergeevich [38]

Answer:

4x+9 if that's not what u needed I can graph it for you too

6 0
3 years ago
The frequency with which a cricket chirps varies directly with the temperature. If the cricket chirps 100 times per minute in 80
Karo-lina-s [1.5K]

The answer is: D) 115

The explanation is shown below:

1. You have that the frequency with which a cricket chirps varies directly with the temperature, which you can express it as following:

y=kx

Where y is the frequency with which a cricket chirps, x is the temperature and k is the constant of proportionality.

2.  If the cricket chirps 100 times per minute in 80° weather, you can calculate k as below:

k=\frac{100}{80}=1.25

3. Therefore, the frequency in 92° weather is:

y=1.25x\\y=(1.25)(92)\\y=115

3 0
2 years ago
PLEASEEE HELP <br><br><br><br><br> Also please don’t send me a link for the answer
Solnce55 [7]
See the image for details

6 0
2 years ago
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