Which is greater, 125 or V30?

Isabelle bought some stationery. 1/3 of them were pencils. 5/8 of the remainder were erasers and the rest were rulers. The cost

kobusy [5.1K]

Answer:

Isabelle spent $52.50 more on Erasers than rulers.

Step-by-step explanation:

Step 1

Find the quantity of each stationery bought in fraction

Let us represent the total fraction of what Isabelle bought as: x

1/3x = quantity of pencils bought

5/8 of the remainder = quantity of erasers bought

The remainder = x - 1/3x = 2/3x

5/8 of 2/3x = 5/8 × 2/3x = 5/12x

Hence, 5/12x = quantity of erasers bought

The rest is rulers

1 - (1/3 + 5/12)

1 - (4 + 5/12)

1 - 9/12

1 - 3/4

= 1/4x

Hence, 1/4 = quantity of rulers bought.

Step 2

We find the number of stationeries that Isabelle bought.

The cost of the stationery is

a Pencil: $1.20

an eraser: $1

a ruler: $0.50.

Total amount spent on stationery = 169.50

We have this equation

1.20 × 1/3x + 1 × 5/12x + 0.50 × 1/4x = 169.50

0.4x + 0.4166666667x + 0.125x =

169.50

0.9416666667x = 169.50

x = 169.50 /0.9416666667

x = 179.99999999

Approximately , the number of stationeries that Isabelle bought = x = 180

Step 3

Find the number and the amount spent on each stationery that Isabelle bought

a) i) Quantity of pencils bought = 1/3 x

x = 180

= 1/3 × 180

= 60 pencils

ii) Amount spent on pencils

If 1 pencil = $1.20

60 pencils =

60 × 1.20 = $72

b) i) Quantity of Erasers bought = 5/12x

x = 180

= 5/12 × 180

= 75 pencils

ii) Amount spent on Eraser

If 1 pencil = $1

75 pencils =

75 × 1 = $75

c) i) Quantity of rulers bought = 1/4 x

x = 180

= 1/4 × 180

= 45 pencils

ii) Amount spent on pencils

If 1 pencil = $0.50

45 pencils =

45 × 0.50 = $22.50

Step 4

We were asked to calculate how much more did she spend on erasers than rulers.

In step 3, the amount spent on Erasers = $75

the amount spent on ruler = $22.5

The difference in the amount spent = $75 - $22.5

= $52.5

Therefore, Isabelle spent $52.50 more on Erasers than rulers.

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3 years ago

C)PLEASE MAN PEOPLE ARE USING ME FOR POINTS

UNO [17]

The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.

Interquartile Range:

Given the Data -> First Quartile = 2, Third Quartile = 5

Interquartile Range = 5 - 2 = 3

Range: 8 - 1 = 7

Variance:

We start by determining the mean,

$\:1+\:2+\:3+\:3+\:3+\:5+\:8 / 7 = 3.57$

n = number of numbers in the set

Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.

$\sum _{i=1}^n\frac{\left(x_i-\bar{x}\right)^2}{n-1},\\\\=> SS/n - 1\\\\=> 31.714/7 - 1\\=> 5.28571$

5.3

Standard Deviation

We take the square root of the variance,

$\sqrt{5.28571} = 2.29906$

2.3

If you are not familiar with variance and standard deviation, just leave it.

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3 years ago

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ANTONII [103]

Answer:

316.41

Step-by-step explanation:

Because if you mutiply to find both volumes then add the volumes together you would get 316.41

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3 years ago

Find the transition matrix from B to B'. B = {(-1,2), (3, 4)), B' = {(1, 0), (0, 1)} STEP 1: Begin by forming the following matr

8_murik_8 [283]

Answer: The required matrix is

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

Step-by-step explanation: We are given to find the transition matrix from the bases B to B' as given below :

B = {(-1,2), (3, 4)) and B' = {(1, 0), (0, 1)}.

Let us consider two real numbers a, b such that

$(-1,2)=a(1,0)+b(0,1)\\\\\Rightarrow (-1,2)=(a,b)\\\\\Rightarrow a=-1,b=2.$

Again, let us consider reals c and d such that

$(3,4)=c(1,0)+d(0,1)\\\\\Rightarrow (3,4)=(c,d)\\\\\Rightarrow c=3,d=4.$

Therefore, the transition matrix is given by

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

Thus, the required matrix is

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

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3 years ago

How to calculate the mode 5 10 12 4 6 11 13 5

Yuki888 [10]

The mode is the number that occurs the most so if you look at the numbers, thee only one that occurs twice is 5 so 5 is the mode.

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3 years ago

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