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4 years ago

Which of the following words does not indicate multiplication?

Mathematics

1 answer:

never [62]4 years ago

4 0

Answer:

D, more than

Step-by-step explanation:

More than is addition / greater than

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List the first 5 mutiplies of 6 9 and 7

NeX [460]

For 6: 12, 18, 24, 30, 36
For 9: 18, 27, 36, 45, 54
For 7: 14, 21, 28, 35, 42

7 0

3 years ago

Read 2 more answers

Given that f(x)=x^2-16x+60 and g(x)=x-10 find f(x)⋅g(x) and express the result in standard form.

storchak [24]

Answer:

x2+44x−10

Step-by-step explanation:

3 0

3 years ago

Hi please i nedd help with these questions .

Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

$\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}$

division sign means that we flip the fraction

$\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}$

now we can multiply all the constants together and all variables

$m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}$

now we can combine all the parts

$\frac{3u^3v}{16m^2}$

#2:

$\frac{24a^2b^3c}{9bc^3}\div\frac{4a^5bc^3}{27a^3b^2c}$

$\frac{24a^2b^3c}{9bc^3}*\frac{27a^3b^2c}{4a^5bc^3}$

$a: (a^2 * a^3)/(a^5) = 1\\b: (b^3 *b^2)/(b*b) = b^3\\c: (c*c)/(c^3*c^3)= 1/(c^4)\\(24*27)/(9*4)= 18$

$\frac{18b^3}{c^4}$

3 0

3 years ago

Read 2 more answers

The number of basketball games that must be scheduled in a league with n teams is given by G(n) = (n2 - n)/2 where each team pla

Pani-rosa [81]

Answer:

There are 7 teams in the league

Step-by-step explanation:

Given that the number of games is given by:

$G(n) = \frac{(n^2-n)}{2}$

The equation will be used to determine the number of games. As we already know, that 21 games are scheduled which means G(n) is 21 so we have to find n when G(n) is 21

Putting this mathematically

$21 = \frac{n^2-n}{2}$