Answer:
Step-by-step explanation:
x³+23x²+162x+360=0
x³+12x²+11x²+132x+30x+360=0
x²(x+12)+11x(x+12)+30(x+12)=0
(x+12)(x²+11x+30)=0
(x+12)[x²+6x+5x+30]=0
(x+12)[x(x+6)+5(x+6)]=0
(x+12)(x+6)(x+5)=0
x=-12,-6,-5
Prior knowledge about precalculus or calculus?
Precalculus comes before calculus 1.
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Always use the formula (y2-y1)/(x2-x1) to find a line’s slope, given two points:
(-1- -8)/(4-5) = 7/-1 = -7
-7 is the slope
Answer:
x+7=7-x or
=-(7-x)
x=3/2 is the only solution
Answer:
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Step-by-step explanation: