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rusak2 [61]
3 years ago
12

5. Is the sequence arithmetic? If so, identify the common difference.

Mathematics
2 answers:
HACTEHA [7]3 years ago
6 0
5.
aritmetic is same increase per term
14 to 21 is 7
21 to 42 is 21
7≠21
no


6.
decreases by 4 each time
an=a1+d(n-1)
an=10-4(n-1)
n=12 for 12th term
a12=10-4(12-1)
a12=10-4(11)
a12=10-44
a12=-34

it is -34



7.
missing term is y
22+n=y
y+n=34
22+n+n=34
22+2n=34
minus 22 from both sides
2n=12
divide both sides by 2
n=6
22+n=y
22+6=y
28=y

28 is answer



5. no
6. -34
7. 28
DerKrebs [107]3 years ago
4 0

Answer:

5. The correct option is 4. No, the given sequence is not arithmetic.

6.The option 3 is correct and the 12th term of the sequence is -34.

7. The option 3 is correct and the missing term of the arithmetic sequence is 28.

Step-by-step explanation:

5.

The given sequence is

14,21,42,77

d_1=a_2-a_1=21-14=7

d_2=a_3-a_2=42-21=21

Since d_1\neq d_2, therefore it is not an arithmetic sequence. Option 4 is correct.

6.

The given sequence is

10,6,2,...

First term is 10 and common difference is -4.

The formula for nth term is

a_n=a+(n-1)d

a_{12}=10+({12}-1)(-4)=10-44=-34

Therefore option 3 is correct and the 12th term of the sequence is -34.

7.

The given sequence is

22, ___ , 34, ...

In an arithmetic sequence

2b=a+c

2b=22+34

2b=56

b=28

Therefore option 3 is correct and the missing term of the arithmetic sequence is 28.

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Answer

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Step-by-step explanation:


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the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
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Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

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So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


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Randomly distributing 45 pencils and 35 markers to his students. what is the probability that the first item he hands out will
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The correct answer 580

Hope this helps

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Is this the correct answer?
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Answer:

Step-by-step explanation:

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