Question

A brick has a base area of 38 1/4 square inches and a height of 2 1/2 inches. What is the volume of the brick?

Answer 1

Answer:

$95\frac{5}{8}\ in^{3}$

Step-by-step explanation:

we know that

The volume of a brick is equal to

$V=Bh$

where

B is the area of the base of the brick

h is the height of the brick

In this problem we have

$B=38\frac{1}{4}\ in^{2}$

$h=2\frac{1}{2}\ in$

Convert to an improper fractions

$B=38\frac{1}{4}\ in^{2}=\frac{38*4+1}{4}=\frac{153}{4}\ in^{2}$

$h=2\frac{1}{2}\ in=\frac{2*2+1}{2}=\frac{5}{2}\ in$

substitute the values

$V=(\frac{153}{4})(\frac{5}{2})=\frac{765}{8}\ in^{3}$

convert to mixed number

$\frac{765}{8}\ in^{3}=\frac{760}{8}+\frac{5}{8}=95\frac{5}{8}\ in^{3}$

Answer 2

multiply the base area by the height

38 1/4 x 2 1/2  = 95 5/8 cubic inches