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SIZIF [17.4K]
3 years ago
11

In the data set below, what are the lower quartile, the median, and the upper quartile?

Mathematics
1 answer:
ivolga24 [154]3 years ago
6 0

Answer:

its 55

Step-by-step explanation:

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The points(1,r) and (5,-4) lie on a line with slope 5. find the missing coordinate r. ​
Arte-miy333 [17]

The value of r is -24

Step-by-step explanation:

Given points are:

(1,r) and (5,-4)

Let the points be:

(x1,y1) = (1,r)

(x2,y2) = (5,-4)

m = 5

The slope is given by:

m = \frac{y_2-y_1}{x_2-x_1}\\5 = \frac{-4-r}{5-1}\\5 = \frac{-4-r}{4}\\5 * 4 = -4-r\\20 = -4-r\\20+4 = -4-r+4\\24 = -r\\r = -24

Hence,

The value of r is -24

Keywords: Slope, coordinates

Learn more about slope at:

  • brainly.com/question/1106840
  • brainly.com/question/10830549

#LearnwithBrainly

5 0
3 years ago
Iq scores follow a normal distribution with mean 100 and standard deviation 15. give 100 random city college students a standard
kipiarov [429]
About 68% of the people will score between 85 and 115.

The values of 85 and 115 are exactly 15 points away, or 1 standard deviation, away from the mean.

According to the empirical rule, about 68% of the values in a normal distribution are within 1 standard deviation of the mean.
4 0
3 years ago
the ratio of pink marbles to white marbles and Tamera's bag is equal to 1:5 what percent of the bag contains pink marbles
harina [27]
Pink to White

1 to 5

1/5 = 0.2

Answer: 20%
5 0
3 years ago
Can someone help with this please?
ipn [44]

7^2=7\cdot7=49\\\\8^2=8\cdot8=64\\\\\sqrt{49}

3 0
3 years ago
Read 2 more answers
$5 PAYPAL + BRAINLIEST TO ANSWER THS
expeople1 [14]

Answer:

Quadratic Equation:

3x^2=2x +5

\text{Standard Form: } 3x^2-2x-5=0

From the standard form of a Quadratic Function, we get:

a=3,\:b=-2,\:c=-5

Discriminant:

\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)

\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5

\Delta=64

From the discriminant, we conclude that the equation will have two real solutions.

State that:

b^2-4ac

b^2-4ac =0:\text{The equation has 1 real solution}

b^2-4ac >0:\text{The equation has 2 real solutions}

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}  $

$x_{2}=\frac{-6}{6} =-1$

5 0
3 years ago
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