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Vaselesa [24]
3 years ago
13

H is between points Q and R. QH=23 and HR=12. What is the length of QR

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

35

Step-by-step explanation:

Given:

GH = 23

HR = 12

Required:

Length big QR

SOLUTION:

Since H is a point in between points Q and R, points Q, H, R are collinear.

QH = 23

HR = 12

QH + HR = QR (segment addition postulate)

23 + 12 = QR (substitution)

35 = QR

Therefore, the length of QR is 35

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The lines represented by the equations y = -X – 3 and
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The equations y = -x -3 and 5y + 5x = -15 represents the same line option 'the same line' is correct.

<h3>What is linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have two equation of the line:

y = -x -3 and

5y + 5x = -15

From the equation 5y + 5x = -15:

Divide by 5 on the above equation:

y + x = -3

or

y = -x -3

The two equations y = -x -3 represents the same line.

Thus, the equations y = -x -3 and 5y + 5x = -15 represents the same line option 'the same line' is correct.

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3 0
1 year ago
If m(x)=x+5/x-1 and n(x) = x – 3, which function has the same domain as (m.n)(x)
meriva

Answer:

The domain of function (m.n)x is same as domain of function m(x).

Step-by-step explanation:

Domain: Any set of input values for which the function is defined and valid.

m(x)=x+5/x-1

Domain of m(x) is x>1 or x<1, x≠1, because if x=1 the function will be undefined.

n(x) = x – 3

Domain of x -3 is -∞<x<∞ i.e all real numbers

(m.n)x = (x+5/x-1)(x-3)

          = (x+5)(x-3)/x-1

The Domain of (m.n)x is x<1 or x>1 or x≠1 because the function is undefined for x=1

So, the domain of function (m.n)x is same as domain of function m(x).

8 0
3 years ago
22. Francisco is three years more than twice Jenna's age. Harrison is two years less than three times Jenna's age.
Jet001 [13]

Answer:

An expression for Francisco's age in terms of a is (2a+3)

An expression for Harrison's age in terms of a is (3a-2)

An expression for the sum of all  three ages, in terms of a is (6a+1)

Step-by-step explanation:

Let

a -----> Jenna's age

b -----> Francisco's age

c -----> Harrison's age

we know that

Francisco's age is two times Jenna's age plus three years

b=2a+3 -----> equation A

Harrison's age is three times Jenna's age minus two years

c=3a-2 ----> equation B

The sum of all  three ages, in terms of a is

(a+b+c) -----> equation C

substitute equation A and equation B in equation C

a+(2a+3)+(3a-2)

Combine like terms

(a+2a+3a)+(3-2)

6a+1

therefore

An expression for Francisco's age in terms of a is (2a+3)

An expression for Harrison's age in terms of a is (3a-2)

An expression for the sum of all  three ages, in terms of a is (6a+1)

6 0
3 years ago
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