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Vaselesa [24]
3 years ago
13

H is between points Q and R. QH=23 and HR=12. What is the length of QR

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

35

Step-by-step explanation:

Given:

GH = 23

HR = 12

Required:

Length big QR

SOLUTION:

Since H is a point in between points Q and R, points Q, H, R are collinear.

QH = 23

HR = 12

QH + HR = QR (segment addition postulate)

23 + 12 = QR (substitution)

35 = QR

Therefore, the length of QR is 35

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Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

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     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

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Therefore, probability that he passed the second exam is 0.784 .

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If MN is a midsegment triangle ABS, find the values of x and y. (picture attached
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90% out of 105% which would be 0.85

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(9x+2)(4x^2+35x-9)=0
pychu [463]
(9x+2)*(4x^2+35x-9)=0

we can make this...

9x+2=0

and

4x^2+35x-9=0

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9x+2=0

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x=\frac{-b\pm\sqrt{b^2-4*a*c}}{2*a}

x=\frac{-35\pm\sqrt{35^2-4*4*(-9)}}{2*4}

x=\frac{-35\pm\sqrt{1369}}{8}

x=\frac{-35\pm37}{8}

x_1=\frac{-35+37}{8}=\frac{1}{4}

x_2=\frac{-35-37}{8}=-9

\boxed{\boxed{S=\{\frac{1}{4},-\frac{2}{9},-9\}}}

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