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Monica [59]
3 years ago
15

10. Simplify (4^3)1/3

Mathematics
2 answers:
dem82 [27]3 years ago
8 0

Answer:

4

Step-by-step explanation:

(4^3)^1/3

4^3 × 1/3

4^3/3

4^1

4

Iteru [2.4K]3 years ago
6 0

Answer:

4

Step-by-step explanation:

The two exponents cancel each other out

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A dairy farm had 9 pastures and 630 cows. The same number of cows are placed in each pasture. How many cows are in each pasture?
rjkz [21]

Answer:


Step-by-step explanation:

if a dairy farm has 630 cows and the same number of cows are placed in each pasture the total number of cows in each pasture is 630

8 0
4 years ago
I am thinking of a number. When I double my number and then subtract the result from five, I get negative one. What is my number
pogonyaev

Answer:

3

Step-by-step explanation:

To turn the word problem into an equation, when we read:

"I am thinking of a number" we write "x"

"when I double my number" we write "2x"

"and then subtract the result from 5" we write "5 - 2x"

"I get negative one" we write "-1 = 5 - 2x"

Now we solve for the number, which is x.

<em>Equation: </em>-1 = 5 - 2x

-1 = 5 - 2x

subtract 5 from both sides

-6 = -2x

divide both sides by -2

3 = x

<h3>There we go! The number is </h3><h2>3</h2>

6 0
3 years ago
Read 2 more answers
Noooooooo Liiiiiiiinnnnnkkkkksssssss... Tanisha and Bess are. Tanisha is half as old Bess. Bess is 6 years older than Tanisha.
goblinko [34]
The answer is D. Tanisha is 6, Bess is 12
5 0
3 years ago
Suppose you have a bag of red, blue, and yellow marbles. If the probability of picking a red marble is1/6 and the probability of
yulyashka [42]
The probabilities of picking a red, blue, and yellow marble must be equal to 1. so

P(R)+P(Y)+P(B)=1

1/6+1/2+P(B)=1  making all terms have a common denominator of 6 we have:

1+3+6P(B)=6

4+6P(B)=6

6P(B)=2

P(B)=2/6

P(B)=1/3
4 0
3 years ago
Which ecpression is equivalent to sqrt 8x^7y^8?
mars1129 [50]

Domain:\ x\geq0\ \wedge\ y\in\mathbb{R}

\sqrt{8x^7y^8}=\sqrt8\cdot\sqrt{x^7}\cdot\sqrt{y^8}=\sqrt{4\cdot2}\cdot\sqrt{x^6\cdot x}\cdot\sqrt{y^{4\cdot2}}\\\\=\sqrt4\cdot\sqrt2\cdot\sqrt{x^6}\cdot\sqrt{x}\cdot\sqrt{(y^4)^2}=2\sqrt2\cdot\sqrt{x^{3\cdot2}}\cdot\sqrt{x}\cdot y^4\\\\=2y^4\sqrt2\cdot\sqrt{(x^3)^2}\cdot\sqrt{x}=2y^4\sqrt{2x}\cdot x^3\\\\=\boxed{2x^3y^4\sqrt{2x}}

Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a\ for\ a\geq0

7 0
4 years ago
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