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4 years ago

PLZ HELP ME???? I think the answer be d

Mathematics

1 answer:

KATRIN_1 [288]4 years ago

8 0

Both number have filled circle meaning that t does contain -3 and 4.
t > equal to -3
t < equal to 4

Answer: B

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It snowed 18 ½ inches in 2 ¾ hours.<br><br> What was the rate of snowfall in inches per hour?

aleksandr82 [10.1K]

Hello There!

It snowed 18.5 inches in 2.75 hours.
Divide both sides by 2.75
2.75/2.75 = 1
18.5/2.75 = 6.72727272727272

Basically it snowed around 6 8/11 inches per hour.

Hope This Helps You!
Good Luck :)

- Hannah ❤

5 0

3 years ago

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Encuentre el radio y el área de círculos cuya circunferencias tienen las siguientes medidas

Vadim26 [7]

Answer:

Los radios de los círculos son $r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$ , respectivamente.

Las áreas de los círculos son $A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$ , respectivamente.

Step-by-step explanation:

La circunferencia ( $s$ ) se calcula mediante la siguiente fórmula:

$s = 2\pi\cdot r$ (1)

Donde $r$ es el radio del círculo.

Una vez hallado el radio, se determina el área de la figura geométrica ( $A$ ) mediante la siguiente fórmula:

$A = \pi\cdot r^{2}$ (2)

Si conocemos que las circunferencias son $s_{1} = 62.8$ , $s_{2} = 12.65$ y $s_{3} = 47.7$ , respectivamente:

1) Radios de los círculos

$r_{1} = \frac{s_{1}}{2\pi}$ , $r_{2} = \frac{s_{2}}{2\pi}$ , $r_{3} = \frac{s_{3}}{2\pi}$

$r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$

2) Áreas de los círculos

$A_{1} = \pi\cdot r_{1}^{2}$ , $A_{2} = \pi\cdot r_{2}^{2}$ , $A_{3} = \pi\cdot r_{3}^{2}$

$A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$

6 0

3 years ago

Mark sold 218 tickets for the school play and made $1,363. Adult tickets are $8 and

Rom4ik [11]

Answer: 91

Step-by-step explanation:

Let adults tickets be a

Let students ticket be b.

The information in the question can be presented as an equation as:

a + b = 218 .......... i

8a + 5b = 1363 ......... ii

Multiply equation i by 5

Multiply equation ii by 1

5a + 5b = 1090 ........ iii

8a + 5b = 1363 ....... iv

Subtract iii from iv

3a= 273

a = 273/3

a = 91

Number of adult's ticket sold = 91

8 0

3 years ago

Robert is adding a In-ground pool to his his back yard. The pool will be 13 m long. 10 m wide and 2m deep . How much water in m

Novay_Z [31]

Answer:

d) 260m^3

Step-by-step explanation:

length x width x height

13*10*2 = 260m³

4 0

3 years ago

Solve for x.<br> -18x-6x=-5

Korvikt [17]

-18x-6x=-5
-24x=-5
x=5/24
This is your answer, my dear~

4 0

4 years ago

Read 2 more answers