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mafiozo [28]
3 years ago
11

I know this easy but what is 8 times 8

Mathematics
2 answers:
Contact [7]3 years ago
8 0
8 times 8 would be 64. :)
satela [25.4K]3 years ago
6 0
8 x 8=64
HOPE THIS HELPS YOU! ^_^
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Idk what to put here lol
Sav [38]

Answer:72

Step-by-step explanation:

The big one is 4 times the small one

6 0
3 years ago
What’s number one and how do You do it
Aliun [14]
I'm assuming you mean #10?

So we're given this equation:

b - 5 = - 5

In this equation, we a variable of <em>b</em>. We want to solve for <em>b</em> by isolating it, or setting it alone. We see that on the side with <em>b</em> on it, it is being subtracted by 5. We want to the opposite in order to isolate <em>b</em>.

Remember that when you do one thing to one side of the equation, you must do it to the other side as well. We can add 5 on both sides to cancel out the negative 5 on the left.

b - 5 = -5&#10;&#10;add 5 on both sides&#10;&#10;b - 5 + 5 = -5 + 5&#10;&#10;simplify&#10;&#10;b = 0

Therefore we know that <em>b</em> does not equal -10, which can be represented as:

b  \neq  -10

So you have to (a) color the hair yellow.
5 0
4 years ago
Read 2 more answers
Evaluate if k = 3.<br> k2 + 5 = [?]
koban [17]

Hey there!

<h2>If \bf{k=3} then substitute it for the \bf{k \ value}</h2><h2>\bf{3^2+5}\\ \bf{3^2\rightarrow 3\times3 = 9} \\ \bf{9+5= 14}\\\boxed{\bf{Answer:14}}}\checkmark</h2><h2>Good luck on your assignment and enjoy your day!</h2><h2>~\frak{LoveYourselfFirst:)}</h2><h2 /><h2 /><h2 />

3 0
3 years ago
Read 2 more answers
Are there any values of x or y which are not possible in the function
Pavel [41]
You must realize that it depends on the function ...
something that you've kept hidden from us.
8 0
3 years ago
Simplify the following expressions
LenKa [72]

Answer:

1.8x+5
2.2x^2-9

Step-by-step explanation:

Given the following questions:

(2x^2+5x-2)+(-2x^2+3x+7)
(2x^2+5x-2)-(5x+7)

In order to find the answer to these questions we have to group the terms with the same variables and then combine like terms. Of course, applying the distributive property if needing to do so.

<u>Number one:</u>
(2x^2+5x-2)+(-2x^2+3x+7)
(2x^2+5x-2)+(-2x^2+3x+7)=2x^2+5x-2-2x^2+3x+7
2x^2+5x-2-2x^2+3x+7
2x^2-2x^2+5x+3x-2+7
2x^2-2x^2=0
5x+3x-2+7
-2+7=5
5x+3x+5
5x+3x=8x
8x+5

<u>Number two:</u>
(2x^2+5x-2)-(5x+7)
(2x^2+5x-2)-(5x+7)=2x^2+5x-2-\left(5x+7\right)
2x^2+5x-2-\left(5x+7\right)
2x^2+5x-2-5x-7
2x^2+5x-5x-2-7
5x-5x=0
2x^2-2-7
-2-7=-9
2x^2-9

Hope this helps.

3 0
2 years ago
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