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3 years ago

Determine the slope of the line that has the following coordinates: (5, 9)(11, - 3)

Mathematics

1 answer:

AlladinOne [14]3 years ago

7 0

Answer:

$x_1 = 5, x_2 =11, y_1 =9, y_2 = -3$

The slope can be founded with this formula:

$m =\frac{y_2 -y_1}{x_2 -x_1}$

And replacing we got:

$m =\frac{-3 -9}{11-5}= -2$

And the best answer for this case would be :

$m=-2$

Step-by-step explanation:

For this case we have the following two points given:

$x_1 = 5, x_2 =11, y_1 =9, y_2 = -3$

The slope can be founded with this formula:

$m =\frac{y_2 -y_1}{x_2 -x_1}$

And replacing we got:

$m =\frac{-3 -9}{11-5}= -2$

And the best answer for this case would be :

$m=-2$

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3 years ago

Read 2 more answers

tim earns $150/week plus $15.00 for each desk he assembles. Write an inequality to represent how many desks he needs assemble to

Gennadij [26K]

x = number of desks needed to make

equation: 150 +15.50x >= 400

solution:

150 +15.50x >=400

15.50x = 250

x = 250/15.50 = 16.129

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3 years ago

Find the solutions to the equation below.<br> Check all that apply.<br> 4x2 + 4x + 1 = 0

Verizon [17]

Answer:

The solution for the given polynomial $4x^2 + 4x+ 1 = 0$ is $x = (\frac{-1}{2})$

Step-by-step explanation:

Here, the given quadratic equation is : $4x^2 + 4x+ 1 = 0$

Now, here solving the given equation by SPLITTING THE MIDDLE TERM:

$4x^2 + 4x+ 1 = 0 = 4x^2 + 2x+ 2x + 1 = 0\\\implies 2x( 2x + 1) + 1(2x + 1) = 0\\\implies (2x +1)(2x +1) = 0\\$

⇒ either (2x+1) = 0, or ( 2x + 1) = 0

⇒ x = -1/2 or x = -1/2

Here, in both the cases, the value of x is equal i.e x = -1/2

So, the given function has TWO IDENTICAL ROOTS.

Hence the solution for the given polynomial $4x^2 + 4x+ 1 = 0$ is $x = (\frac{-1}{2})$

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3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

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2 years ago

What’s the right answers?

Umnica [9.8K]

The answer will be D

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