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3 years ago

Determine the slope of the line that has the following coordinates: (5, 9)(11, - 3)

Mathematics

1 answer:

AlladinOne [14]3 years ago

7 0

Answer:

$x_1 = 5, x_2 =11, y_1 =9, y_2 = -3$

The slope can be founded with this formula:

$m =\frac{y_2 -y_1}{x_2 -x_1}$

And replacing we got:

$m =\frac{-3 -9}{11-5}= -2$

And the best answer for this case would be :

$m=-2$

Step-by-step explanation:

For this case we have the following two points given:

$x_1 = 5, x_2 =11, y_1 =9, y_2 = -3$

The slope can be founded with this formula:

$m =\frac{y_2 -y_1}{x_2 -x_1}$

And replacing we got:

$m =\frac{-3 -9}{11-5}= -2$

And the best answer for this case would be :

$m=-2$

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What is the digit in 913 and where's the digit in the tens place and the value of the digit tens someone answer for my homework

lorasvet [3.4K]

4. Period with the digits 913 is called thousands period.
5. The digit in the ten thousand place is 1.
6. The value of 9 is hundred thousands.

Hope it will help you :)

3 0

3 years ago

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If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$

$A2=(4)(x)=4x\ in^2$

$A3=(x)(7)=7x\ in^2$

$A4=(4)(7)=28\ in^2$

The total area of the second rectangle is the sum of the four areas

$A=A1+A2+A3+A4$

State the product of (x+4) and (x+7) as a trinomial

$(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28$

Part c) If the original square had a side length of x = 2 inches, then what is the area of the second rectangle?

we know that

The area of the second rectangle is equal to

$A=A1+A2+A3+A4$

For x=2 in

substitute the value of x in the area of each portion

$A1=(2)(2)=4\ in^2$

$A2=(4)(2)=8\ in^2$

$A3=(2)(7)=14\ in^2$

$A4=(4)(7)=28\ in^2$

$A=4+8+14+28$

$A=54\ in^2$

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

$A(x)=x^{2} +11x+28$

For x=2 in

substitute and solve for A(x)

$A(2)=2^{2} +11(2)+28$

$A(2)=4 +22+28$

$A(2)=54\ in^2$ ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0

3 years ago

Can someone please help me with this ⬆️⬆️⬆️it's the picture above ... 13/78=×/12

ratelena [41]

I am pretty sure x=2

3 0

3 years ago

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You roll two standard number cubes. What is the probability that the sum is odd, given than one of the number cubes shows a 1?

Virty [35]

It's not specified whether 1 is the 1st or 2nd roll: HOWER:

The 1st Roll is "1": P(odd sum/the 1st Roll is 1)
What is the sample space of all numbers starting with "1":
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the couple of add sum=(1,2), (1,4), (1,6), =3
P(odd sum/ 1st is 1) = 3/6 =1/2
or in applying the formula:

P(odd sum/the 1st Roll is 1) =P(odd sum ∩ 1) / P(getting "1") it will give the same probability = 1/2

NOW if the 2nd Roll is "1", it 's still 1/2

6 0

3 years ago

Which of the following is NOT an integer? 1,-3,0,0.25

Darya [45]

Answer:

0.25

Step-by-step explanation:

Fractions and decimals are not integers. Any and all whole numbers, 1, 2,3, 4, -1, -2, -3, -4 etc. are integers. 0.25 is a decimal and therefore not an integer.

Hope this helps and have a nice day!

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3 years ago

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