He sum of three consecutive integers is −369−369. find the three integers.

Mathematics

1 answer:

Alinara [238K]3 years ago

4 0

N + (n+1) + (n+2) = -369
3n + 3 = -369
3n = -366
n = -122

so the three consecutive integers are : -124 ; -123 ; -122

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<img src="https://tex.z-dn.net/?f=%285%5E%7B3%7D%29%5E%7B-3%7D" id="TexFormula1" title="(5^{3})^{-3}" alt="(5^{3})^{-3}" align="

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$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$( { {5}^{3} })^{ - 3} \\ \\ which\:means \:that \: {5}^{3}\: is \:multiplied \:thrice\: with\: itself\\ \\ = {5}^{3 \times - 3} \\ \\ = {5}^{ - 9} \\ \\= \frac{1}{ {5}^{9} } \\ \\ = \frac{1}{5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5} \\ \\ = \frac{1}{1953125}$

<u>Note</u>:-

$( { {a}^{m} })^{n} = {a}^{m \times n}$

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$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}$

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