Question

Which compound inequality can be used to solve the inequality |3x+2|>7? -7<3x+2>7 -7>3x+2>7 3x + 2 > –7 or 3x + 2 > 7 3x + 2 < –7 or 3x + 2 > 7

Answer 1

Answer:

$(3x+2)< -7$  or   $(3x+2) > 7$

Step-by-step explanation:

we have

$\left|3x+2\right|>7$  

Divide the absolute value inequality into two inequalities

First inequality (positive value)

$(3x+2) > 7$

Second inequality (negative value)

$-(3x+2) > 7$

Multiply by -1 both sides

Remember that when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

so

$(3x+2)< -7$

therefore

The compound inequality that can be used is

$(3x+2)< -7$  or   $(3x+2) > 7$

Answer 2

Answer:

D) 3x + 2 < –7 or 3x + 2 > 7

Step-by-step explanation:

this is correct on ed-genuity, hope this helps! :)