It started at 20.....then dropped 31 degrees
20 - 31 = - 11 <== its 11 below zero
Answer:
Population of mosquitoes in the area at any time t is:

Step-by-step explanation:
assume population at any time t = P(t)
population increases at a rate proportional to the current population:
⇒dP/dt ∝ P
----(1)
where k is constant rate at which population is doubled
solving (1)

---- (2)
initial population = 400,000
population is doubled every week
⇒P(1)=2P(0)
Using (2)


In presence of predators amount is decreased by 50,000 per day
Then amount decreased per week = 350,000
In this case (1) becomes
---(3)
solving (3) by calculating integrating factor

Multiplying I.F with all terms of (3)

Integrating w.r.to t




at t=0



So, population of mosquitoes in the area at any time t is

Answer:
Can i get brainly I need 2 more to level up
Step-by-step explanation:
Answer:
0.0035289
Step-by-step explanation:
From the question;
mean annual salary = $63,500
n = sample size = 31
Standard deviation = $6,200
Firstly, we calculate the z-score of $60,500
Mathematically;
z-score = x-mean/SD/√n = (60500-63500)/6200/√(31) = -2.6941
So we want to find the probability that P(z < -2.6941)
We can get this from the standard normal table
P( z < -2.6941) = 0.0035289