X+ 3y = 13
(y - 3) + 3y =13
4y - 3 = 13
4y -3 + 3 = 13+3
4y = 16
4y/4 = 16/4
y=4
x = 4 - 3
x = 1
A) (1, 4)
Check x+3y =13
1+ 3(4) =13
1 + 12=13
13=13
The mean of a distribution is the sum of the data elements divided by the count of the dataset.
<em>The mean of the distribution is 4</em>
The complete table is given as
![\left[\begin{array}{cc}People & Frequency &0 - 2 & 5 & 3 - 5 & 25 & 6 - 8 & 5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DPeople%20%26%20Frequency%20%260%20-%202%20%26%205%20%26%203%20-%205%20%26%2025%20%26%206%20-%208%20%26%205%5Cend%7Barray%7D%5Cright%5D)
The complete question requires that, we calculate the mean of the dataset
First, we calculate the class midpoint
This is the average of the class interval
<u />
<u>For interval 0 - 2, </u>

<u>For interval 3 - 5,</u>

<u>For interval 6 - 8</u>

So, the table becomes
![\left[\begin{array}{ccc}People & x & Frequency &0 - 2 &1 & 5 & 3 - 5 & 4& 25 & 6 - 8& 7 & 5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DPeople%20%26%20x%20%26%20Frequency%20%260%20-%202%20%261%20%26%205%20%26%203%20-%205%20%26%204%26%2025%20%26%206%20-%208%26%207%20%26%205%5Cend%7Barray%7D%5Cright%5D)
The mean is then calculated as:

This gives



Hence, the mean of the distribution is 4
Read more about mean at:
brainly.com/question/17060266
70-47=23
I think this is what you are talking about
Y=v(initial)*t+1/2at^2
since the velocity is zero at the maximum height then we get
y=1/2at^2
a is just acceleration due to gravity so a=g which is 9.8 m/s^2.
so y=1/2gt^2.