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3 years ago

15

Anthony deposit $500 into his bank account. A couple of days later he withdrew $40 . The next day he deposited $30. A day later,

he withdrew $100. How much money left in his account?

1 answer:

Yakvenalex [24]3 years ago

5 0

Answer:

$390

Step-by-step explanation:

so he has $500

he took $40,which is $460

then he put in $30,$490

then he took away $100,$390

hopefully you understand

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A.) 15.7in<br> B.) 31.4in<br> C.) 40in<br> D.) 62.8in

IrinaK [193]

Answer:

31.4 in

Step-by-step explanation:

This is a tricky question,

if you observe the shape carefully, you will notice that if you mirror (flip outward) each curve surface of each quardrant, what you will end up with is a complete circle with a radius of 5 inches.

Hence the combined length of all the curved surfaces is simply the circumference of the circle, given by:

Circumference = 2πr

= 2 x 3.14 x 5

= 31.4 in

4 0

2 years ago

Read 2 more answers

∠xangle, x and \angle y∠yangle, y are supplementary angles. \angle y∠yangle, y measures 88^\circ88

Yuliya22 [10]

Answer:

92∘

Step-by-step explanation:

Supplementary angles combine to create a straight angle. So, they have a sum of 180.

∠x + ∠y

∠x + 88 --------------> 180

=92∘

4 0

3 years ago

Justify your reasoning

love history [14]

Answer:

Yes

Step-by-step explanation:

You can conclude that ΔGHI is congruent to ΔKJI, because you can see/interpret that there all the angles are congruent with one another, like with vertical angles (∠GIH and ∠KIJ) and alternate interior angles (∠H and ∠J, ∠G and ∠K).

We also know that we have two congruent sides, since it provides the information that line GK bisects line HJ, meaning that they have been split evenly (they have been split, with even/same lengths).

<u><em>So now we have three congruent angles, and two congruent sides. This is enough to prove that ΔGHI is congruent to ΔKJI,</em></u>

<u><em /></u>

7 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0

2 years ago

How are all angles in the 4th quadrant, negative or positive?

anastassius [24]

Answer:

They are all positive because you must go right.

They are all negative because you must go down.

Step-by-step explanation:

Example. (1,-4)

You go over one.

Down 4

5 0

3 years ago