Question: "A coin is tossed 8 times. Find the probability P(of exactly 6 occurrences of tails)"
Answer:
When we toss a coin we have 50% of probability to get a tail and 50% probability to get heads.
If we toss the coin 8 times, in order to find P(T=6), we need to use the binomial distribution:
where:
n = total number of events
k = number of successes we want
p = probability of success
Therefore:
<span>
</span>
= 28 · 0.015625 · 0.25
= 0.109375
Hence, the probability of getting 6 tails out of 8 tosses is D) 10.94%.
Answer:
1/2×+12=10, x=-4
Step-by-step explanation:
Just trust me on this
Answer:
3x^2 + 12x + 4y^2 - 8y = 32
Step-by-step explanation:
3(x^2+4x)+4(y^2-2y)=32
At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:
or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32
or, 3x^2 + 12x + 4y^2 - 8y = 32
Since the equation does not have anything to add or deduct, therefore, it is the answer.
2√31
I DONT KNOW!
THERES NO EXPLAINATION IN MATH.. LETS BE HONEST HERE.