Help help help please

Mathematics

2 answers:

baherus [9]3 years ago

7 0

Hello there! :)

First, we have to get rid of the fraction by multiplying both sides by 3:

2x+8≥12

Now, we move all the numbers (constants) to the right:

2x≥12-8

2x≥4

Divide both sides by 2:

x≥2

<h2>Therefore, x≥2</h2>

Hope it helps you!

~Just a felicitous girlie

#HaveAGreatDay

$SilentNature :)$

Ksivusya [100]3 years ago

4 0

<h2>>> Asnwer</h2>

________

$\:$

$\frac{2x + 8}{3} \geqslant 4$

$2x + 8 \geqslant 4 \times 3$

$2x + 8 \geqslant 12$

$2x \geqslant 12 - 8$

$2x \geqslant 4$

$x \geqslant 2$

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