Question

Help help help please

Answer 1

Hello there! :)

First, we have to get rid of the fraction by multiplying both sides by 3:

2x+8≥12

Now, we move all the numbers (constants) to the right:

2x≥12-8

2x≥4

Divide both sides by 2:

x≥2

Therefore, x≥2

Hope it helps you!

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Answer 2

>> Asnwer

________

$\:$

$\frac{2x + 8}{3} \geqslant 4$

$2x + 8 \geqslant 4 \times 3$

$2x + 8 \geqslant 12$

$2x \geqslant 12 - 8$

$2x \geqslant 4$

$x \geqslant 2$