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leva [86]
3 years ago
14

If a single die is rolled twice there are how many possible outcomes

Mathematics
1 answer:
sergiy2304 [10]3 years ago
3 0
Total number of possible outcomes = 36
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4. What is the volume of the composite figure?​
GaryK [48]

Answer:

36 sq ft

Step-by-step explanation:

1×2×3=6

1×4×3=12

1×6×3=18

6+12+18=36

7 0
3 years ago
Which is true of dependent events?
insens350 [35]

Answer:

Might be

Step-by-step explanation:

A.) The probability of all dependent events can be calculated using the OR formula

5 0
3 years ago
Consider the diagram below. Which of the following statements are correct? Select all that apply. (Diagram and answer options ar
Vika [28.1K]

Answer:

Options 1,2,6,7 are correct statements.

Step-by-step explanation:

In the given figure lines m and n are cut by a transversal t.

Among all the statements the options that are correct are :

1)<1 and <5 are corresponding angles.(The angles in matching corners are called corresponding angles)

2)<3 and <6 are alternate interior angles .(The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles)

6)<4 and <6 are same side consecutive angles.(consecutive angles lie on the same side of the transversal)

7)<1 and <8 are alternate exterior angles.( These angles lie on the exterior side of the lines and on opposite side of the transversal)

3 0
3 years ago
On average 83.1% of welds performed by a particular welder are defective. if, in one day, the welder creates three welds. what i
Nuetrik [128]
Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.

Using the binomial distribution, we want all three to be defective.
P(X = 3) = \binom{3}{3}(p)^{3}{q}^{3 - 3}
P(X = 3) = \binom{3}{3}(0.831)^{3}(1)
P(X = 3) = (0.831)^{3} \approx 0.573856191
4 0
3 years ago
The product of 2 and the sum of a number and 8 is equivalent to 16.
Trava [24]

Answer:b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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