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4 years ago

Find the quotient 12a3p4 ÷ -2a2p

Mathematics

2 answers:

babunello [35]4 years ago

8 0

Your answer would be, -6ap^3

ss7ja [257]4 years ago

5 0

12a3p4 ÷ -2a2p

= - 6ap^3
.........................................

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Please help asap

eimsori [14]

Answer:

The system of inequalities are

x - y < 1 and y < - 2

Step-by-step explanation:

The horizontal line shown in the graph has equation y = - 2 {As it is parallel to x-axis}

Now, this line is dotted and the lower portion of the graph is shaded.

So, the inequality will be y < - 2 ......... (1)

Again, another line is there in the graph which passes through the points (1,0) and (0,-1)

So, its equation will be $\frac{y + 1}{- 1 - 0} = \frac{x - 0}{0 - 1}$

⇒ y + 1 = x

⇒ x - y = 1

Now, the origin (0,0) is within shaded zone of the inequality and putting x = 0 and y = 0, we get

0 - 0 < 1

So, the equation of the inequality is x - y < 1 {As the line is dotted}

Therefore, the system of inequalities are

x - y < 1 and y < - 2 (Answer)

8 0

3 years ago

A recipe for 10 servings of raspberry sorbet calls for 2 cups of water, mc017-1.jpg cups of granulated sugar, and 4 cups of froz

Lana71 [14]

Answer: A: 4 gallons don't worry i got it correct.

5 0

3 years ago

Read 2 more answers

Can someone tell if it the first second third or fourth

Vikki [24]

Answer:

B.) Line ED Corespondes to line AD

Step-by-step explanation:

8 0

3 years ago

Are the two expressions equivalent ×=10? 5(3×+8) 8×+8

REY [17]

5(3*10+8)=190
8*10+8=88
they are not equivalent , not equal

5 0

4 years ago

For which value(s) of the constant k is the circle x² + (y − k)² = 16 tangent to the line y = 3?

STALIN [3.7K]

Answer:

Step-by-step explanation:Let us find points of intersection of line

3

x

+

4

y

−

k

=

0

and circle

x

2

+

y

2

=

16

. We can do this by putting value of

y

from first equation i.e.

y

=

k

−

3

x

4

and we get

x

2

+

(

k

−

3

x

)

2

16

=

16

or

16

x

2

+

k

2

+

9

x

2

−

6

k

x

=

256

i.e.

25

x

2

−

6

k

x

+

k

2

−

256

=

0

This would give two values of

x

and corresponding two values of

y

i.e. two points. But tangent cuts the circle in only at one point. This will be so when discriminant is zero i.e.

(

−

6

k

)

2

−

4

⋅

25

⋅

(

k

2

−

256

)

=

0

or

−

64

k

2

+

25600

=

0

or

k

=

±

20

graph{(x^2+y^2-16)(3x+4y-20)(3x+4y+20)=0 [-10, 10, -5, 5]}

5 0

4 years ago

Read 2 more answers