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Montano1993 [528]
3 years ago
6

Solve each inequality 1 < x -2

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
7 0
Add 2 to both sides...x>3
Amanda [17]3 years ago
4 0
Add 2 to both sides...x>3 ok 
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Salsk061 [2.6K]
You can’t really answer this without showing us the the answer you got from item 6
8 0
3 years ago
Solve the system of equations y=5x-1 y=9x-9
Leto [7]

Answer:

Look at the equations:

y

=

−

9

x

−

21

and

y

=

5

x

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7

Because both equations equal (y), they both equal the same.

If an equations says "

y

=

−

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x

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21

" , that means we can replace (y) with

−

9

x

−

21

.

Therefore when i take the equation:

y

=

5

x

+

7

, we can replace (y) to get:

−

9

x

−

21

=

5

x

+

7

Now isolate (x):

−

9

x

−

21

=

5

x

+

7

⇔

−

21

=

14

x

+

7

⇔

−

28

=

14

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−

2

7 0
2 years ago
Please help <br> Question: 6b = 18<br> Answer: ?
ratelena [41]

Answer:

6b=18

b=18/6

b=3

.

.

.

.

.

.

3 0
3 years ago
Read 2 more answers
Which equation is not equivalent to the other two
Liula [17]

Answer:

y=-4-3x

Step-by-step explanation:

y = -3x - 4

y = -3x + (-4)

y = -4 + 3x

y = -4 - 3x

7 0
3 years ago
15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>​
Sav [38]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

It looks like we're given

\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

\cos^2t=\dfrac{1+\cos(2t)}2

\sin^2t=\dfrac{1-\cos(2t)}2

so that

\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}

Then we have

\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t

\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}

\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}

where the last reduction follows from dividing through everything by \cos(2t)\cos^2t and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0
3 years ago
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