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4 years ago

Please help me on these two questions!

Mathematics

1 answer:

Anit [1.1K]4 years ago

6 0

1. (5b8 + 8c) • (5b8<span> - 8c)
2. </span>7x(2y + x)(-2y + x)<span> :) </span>

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Pls do it fast

galina1969 [7]

Answer:

solution :

in the given figure AB=10.2cm, AC=14cm, AD=DC and AD perpendicular to BC.

now ,

in rt angle tirangle ADC,

angleACD=45 degree, angle DAC=45 degree now,

in triangle ABD,

angle BAD+angleABD+angleADB=180 DEGREE (sum of the sngle of triangle)

angle BAD+75+30=180

angle BAD=180-165 therefore,angle BAD=15

angle BAC =15+45=60

Area of triangle ABC=1/2×AB×AC×SIN 60

=1/2×10.2×14×√3/2

=61.83cm³ ans

3 0

3 years ago

Answer the question in the picture.

steposvetlana [31]

Answer: 6

Remember: 0.3 repeated = $\frac{1}{3}$

$3 \frac{2}{3} + 2 \frac{1}{3} = 5\frac{3}{3}\\\\5\frac{3}{3} = 6$

5 0

3 years ago

Read 2 more answers

Want points answer me question

WITCHER [35]

Answer:

$110

Step-by-step explanation:

1. The total cost:

<em>(3 * 65) + (2 * 70) + (1 * 55)</em> -> cost of dresses + jeans + earrings

Total: 195 + 140 + 55 = <em>390</em>.

2. Money leftover:

<em>500 - 390</em> = $110.

4 0

3 years ago

4. Bob’s piece of paper weighs 1,500 grams. Sue’s paper weighs 2,400 grams. How much heavier is Sue’s piece than Bob’s paper, in

Crazy boy [7]

1,500
2,400
1,100. Sue’s paper is 1,100 kilograms
then Bob’s paper

3 0

3 years ago

Read 2 more answers

The figure shows the layout of a symmetrical pool in a water park. What is the area of this pool rounded to the tens place? Use

k0ka [10]

Answer:

$2489ft^{2}$

Step-by-step explanation:

The pool are is divided into 4 separated shapes: 2 circular sections and 2 isosceles triangles. Basically, to calculate the whole area, we need to find the area of each section. Due to its symmetry, both triangles are equal, and both circular sections are also the same, so it would be enough to calculate 1 circular section and 1 triangle, then multiply it by 2.

<h3>Area of each triangle:</h3>

From the figure, we know that <em>b = 20ft </em>and <em>h = 25ft. </em>So, the area would be:

$A_{t}=\frac{b.h}{2}=\frac{(20ft)(25ft)}{2}=250ft^{2}$