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2 years ago

Leola ran in a 10-kilometer race. About how many miles did she run

Mathematics

1 answer:

kirza4 [7]2 years ago

7 0

The answer is that Leola ran 6.2

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What is the value of m∠3 if m∠5=70° and m∠2=60°?

Roman55 [17]

Answer : 50

Explanation : All angles of a triangle add up to 180

7 0

3 years ago

Could anyone help please i am very bad at math :( what is 3/5 of 50

artcher [175]

3/5(50)
=(3/5)(50/1)
=(3)(50)/(5)(1)
=150/5
=30

8 0

3 years ago

In two years tom will be twice as old as 5 years ago how old is tom

lisabon 2012 [21]

In two years tom will become 10 years old
Because 5×2=10

3 0

3 years ago

RSM HOMEWORK HELP!!! PLEASE HELP ME ASAP!!

frutty [35]

Answer:

x = 27

Step-by-step explanation:

AC // DE

m∠ABD ≅ m∠BDE = 72°

m∠ADB + m∠BDE + m∠EDF = 180°

2x + 72° + 2x = 180°

4x = 108°

x = 27°

4 0

3 years ago

Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3

solmaris [256]

Given:

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

Now,

$\cos (u)=-\sqrt{1-\sin^2 (u)}$

$\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}$

$\cos (u)=-\sqrt{1-\dfrac{49}{625}}$

$\cos (u)=-\sqrt{\dfrac{625-49}{625}}$

On further simplification, we get

$\cos (u)=-\sqrt{\dfrac{576}{625}}$

$\cos (u)=-\dfrac{24}{25}$

Similarly,

$\sin (v)=-\sqrt{1-\cos^2 (v)}$

$\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}$

$\sin (v)=-\sqrt{1-\dfrac{16}{25}}$

$\sin (v)=-\sqrt{\dfrac{25-16}{25}}$

$\sin (v)=-\sqrt{\dfrac{9}{25}}$

$\sin (v)=-\dfrac{3}{5}$

Now,

$\cos (u-v)=\cos u\cos v+\sin u\sin v$

$\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)$

$\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}$

$\cos (u-v)=\dfrac{1 17}{625}$

Therefore, the value of cos (u-v) is 0.1872.

6 0

3 years ago