Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 90 grams, hence
.
- The standard deviation is of 1 gram, hence
.
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:



The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
- Looking at the z-table, Z = -3 has a p-value of 0.0013.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213
It is asking you to move the right formula with its match.
Formula for a cylinder: π*R^2*HSo the first option goes to the first shape.Example:
Radius=5
Length=10
π≈3.14
3.14*5²*10
=725 cm³ for the answer.
Formula for a square: l*w*hSo the 4th option goes with the 2nd shape. Example: l=5 w=5 h=5
(Length * Width * Hieght)
5*5*5=125 for the answer.
Formula for a cone is: 1/3π*r^2*hSo the second option goes to the 3rd shape.
Example: r=3 h=11
π≈3.14

33 is your answer.
Formula for the pyramid would be: 1/3*b*hSo the 3rd option would go to the 4th shape.Example:
b=2 h=10

Rounded: 6.6
Hope this helps!~
(Look at the attachment)
<u>Answer:</u> The ratio that represents the cosine of ∠T is 
<u>Step-by-step explanation:</u>
We are given:
UV = 56 units
VT = 33 units
UT = 65 units
∠V = 90°
Cosine of an angle is equal to the ratio of base and the hypotenuse of the triangle. ΔTUV is drawn in the image below.

Base of the triangle is UV and the hypotenuse of the triangle is TU
Putting values in above equation, we get:

Hence, the ratio that represents the cosine of ∠T is 