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leva [86]
3 years ago
6

Hi does any one know how to solve this y=__x+__

Mathematics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

y = 50x + 25

Step-by-step explanation:

y = mx + b

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(2,3) is your answer for the equation
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3 years ago
A square number and a multiple of 3 have a total of 90 what r the 2 numbers
Alecsey [184]

Hello,

Let's x² the square number

and 3*y the multiple of 3.

x^2+3y=90\\\\\boxed{y=-\dfrac{1}{3} x^2+30}\\\\

2 solutions : for (x,y) as integers : (-6,18) and (6,18)

but one solution for (x²,3y) as integers :<u> (36,54) </u>

7 0
2 years ago
True or false the difference between consecutive perfect square numbers is always odd
ipn [44]
Hi,
That would be true.
4 0
3 years ago
The Eagles basketball team scored 12 more than 2 times as many points in the last game of the season than in the first game. Whi
lesya692 [45]

Answer:

A. 12+2p

G. p+p+12

Step-by-step explanation:

The Eagles basketball team scored 12 more than 2 times as many points in the last game of the season than in the first game

Number of points scored in the last game of the season = 2p + 12

A. 12+2p

Equivalent

B. 2+p+12

= P + 14

Not equivalent

C. 2+12p

Not equivalent

D. p(2+12)

= 2p + 12p

Not equivalent

E. p+2+12

= P + 14

Not equivalent

F. 12p+2p

Not equivalent

G. p+p+12

= 2p + 12

Equivalent

3 0
2 years ago
A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year. This situation
lubasha [3.4K]

Answer:

This situations represents the depth of the lake after t years.

The rate of decay is equal to 0.02 a year.

So the depth of the lake each year is 0.98 times the depth in the previous year.

It will take 5.77 years for the depth of the lake to reach 26.7 meters.

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the decay of an amount is given by:

D(t) = D(0)(1-r)^t

In which D(0) is the initial amount and r is the decay rate, as a decimal.

A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year.

This means that D(0) = 30, r = 0.02

So

D(t) = D(0)(1-r)^t

D(t) = 30(1-0.02)^t

D(t) = 30(0.98)^t

This situation represents

The depth of the lake after t years.

The rate of growth or decay, r, is equal to

The rate of decay is equal to 0.02 a year.

So the depth of the lake each year is times the depth in the previous year.

1 - 0.02 = 0.9

So the depth of the lake each year is 0.98 times the depth in the previous year.

It will take between years for the depth of the lake to reach 26.7 meters.

This is t for which D(t) = 26.7. So

D(t) = 30(0.98)^t

26.7 = 30(0.98)^t

(0.98)^t = \frac{26.7}{30}

\log{(0.98)^t} = \log{\frac{26.7}{30}}

t\log{(0.98)} = \log{\frac{26.7}{30}}

t = \frac{\log{\frac{26.7}{30}}}{\log{0.98}}

t = 5.77

It will take 5.77 years for the depth of the lake to reach 26.7 meters.

4 0
2 years ago
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