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andrey2020 [161]
3 years ago
15

An airplane is traveling at 1,500 miles/minute and then 5 minutes later reaches a speed of 1800 miles/second. What is the averag

e acceleration of the airplane?
Mathematics
1 answer:
adell [148]3 years ago
8 0
The answer to the problem is 60
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HELP AND NO LINKS HELP
nignag [31]

Answer:

b.

Step-by-step explanation:

Each of the provided angles are also a part of linear pairs, so 180-145=35

180-100=80

35+80=115

To solve for the final angle/the one they are wanting

180-115=65

4 0
2 years ago
You have to answer 3 essay questions for an exam. There are 6 essays to choose from. How many different groups of 3 essays could
Paladinen [302]

Answer:

The answer is 120

Step-by-step explanation:

3 places. 6 options in the first place, 5 options in the second place, and then 4 in the last place. Because one option is used every time you pick one.

6x5x4=120

3 0
3 years ago
The volume of a large tank is 210 ft3. It is 5 3/5
IRISSAK [1]

Answer:

20 5/6 ft

Step-by-step explanation:

5 3/5 = 28/5

1 4/5 = 9/5

V = l * w * h

210 = l * 28/5 * 9/5

210 = l * 252/25

multiply both sides by 25/252

5250/25 = l

Reduce

20 5/6 = l

20 5/6 ft

6 0
2 years ago
Hi pls help me ty in advance​
Anna35 [415]

A right angle = 90 degrees

A round angle = 360 degrees


1. 3 x 90 = 270 degrees

2. 4 x 90 = 360 degrees

3. 1 1/2 x 90 = 135 degrees

4. 2 1/3 x 90 = 210 degrees

5. 2/9 x 360 = 80 degrees

6. 3 3/8 x 360 = 1,215 degrees

5 0
2 years ago
Find the angles between -pi and pi that satisfy:<br><br> (−√3) sin(v)+cos(v)=√3
MAXImum [283]

Observe that

\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v

In the original equation, divide both sides by \dfrac12:

-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2

\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2

Next,

\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi

where n is any integer. Then

\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi

Fix n=0 to ensure -\pi, so that

v=-\dfrac\pi6,v=-\dfrac\pi2

3 0
3 years ago
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