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andrey2020 [161]
4 years ago
15

An airplane is traveling at 1,500 miles/minute and then 5 minutes later reaches a speed of 1800 miles/second. What is the averag

e acceleration of the airplane?
Mathematics
1 answer:
adell [148]4 years ago
8 0
The answer to the problem is 60
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Solve the system of linear equations by elimination −2x+3y=7 and 5x+8y=−2
forsale [732]
You would need to make them eliminate so I would multiply the entire first one by 2.5 to make the X's cancel out. So you would end up with -5X+7.5Y=17.5. The X's would cancel and you would be left with 15.5Y=15.5. So Y=1. Then replace Y into one of the equations. I'm going to use the top again. -2X+3(1)=7. Subtract 3 from both sides to get -2x=4. Divide both sides by negative 2 to get X=-2. So the solution would be (-2,1)
4 0
3 years ago
If Herschel walker can sprint 40 meters in 4.35 seconds, how many miles per hour is he running? Round to the nearest tenth
-BARSIC- [3]

Answer:

B) 20.6 mi/hr

Step-by-step explanation:

To solve this, we need to first convert 40 meters to mile, then convert 4.35 seconds to hour, then solve by proportion.

converting 40 meters to mile;

1 mile = 1609.344 meter

x       = 40 meters

1609.344x = 40

x = 40/1609.344

x =0.02485 mile

Then converting seconds to hour

1 hour = 3600 seconds

 y      = 4.35 seconds

3600 y = 4.35

y=4.35/3600

y =0.00121  hour

Using proportion to solve the question

Let n be the number he runs miles per hour

0.02485 mile = 0.00121  hour

  n                   = 1    hour

cross-multiply

0.00121  n =   0.02485

Divide both-side by 0.00121

0.00121  n/0.00121  =   0.02485/0.00121

n ≈ 20.6 mile/hour

Therefore, he is running 20.6 mi/hr

5 0
4 years ago
Question 10 Express 40 as a product of prime factors​
Step2247 [10]

Answer:

2 x 2 x 2 x 5

Step-by-step explanation:

The first few prime numbers:  {2, 3, 5, 7, 11, 13, 17, 19}

One way to start is to divide by the first prime until you can't do that any more, then try the next prime and so on until all the numbers in your list are prime.

40 = 2(20)  divide 20 by 2 again

40 = 2(2)(10)  divide 10 by 2 again

40 = 2(2)(2)(5) stop--all factors are prime.

5 0
3 years ago
How many solutions does the equation have?
Elina [12.6K]

9514 1404 393

Answer:

  1 solution

Step-by-step explanation:

The coefficients of d are different on the two sides of the equation (3d vs 6d), so the equation has one solution.

__

Dividing by 3 gives ...

  d +11 = 2(d +33)

  d + 11 = 2d + 66

Adding -d-66 to both sides gives ...

  -55 = d . . . . . . the one solution

4 0
3 years ago
How many 'words' can be made from the name ESTABROK with no restrictions
Bumek [7]

The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

<h3>How to determine the number of ways</h3>

Given the word:

ESTABROK

Then n = 8

p = 6

The formula for permutation without restrictions

P = n! ( n - p + 1)!

P = 8! ( 8 - 6 + 1) !

P = 8! (8 - 7)!

P = 8! (1)!

P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1

P = 40, 320 ways

Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

Learn more about permutation here:

brainly.com/question/4658834

#SPJ1

6 0
2 years ago
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