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Inga [223]
3 years ago
14

6 eggs weigh 3/4 of a pound. How much does each egg weigh?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
8 0

Each\: egg\: weight: \frac{3}{4}  \div 6 =  \frac{1}{8}  \: of \: a \: pound

steposvetlana [31]3 years ago
5 0

3/4÷6/1=?

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

3/4×1/6=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

3×1/4×6=3 2/4

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 3 and 24 using

GCF(3,24) = 3

3÷324÷3=18

Therefore:

3/4÷6/1=1/8

Solution by Formulas

Apply the fractions formula for division, to

34÷61

and solve

3×14×6

=324

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(3,24) = 3

3÷324÷3=18

Therefore:

3/4÷6/1=1/8

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Find the value of X: 3x (-35) = 2x
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The label on the car's antifreeze container claims to protect the car between −40°C and 125°C. To covert Celsius temperature to
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Answer:

see below

Step-by-step explanation:

The label on the car's antifreeze container claims to protect the car between -40°C and 125°C.

So inequality which models this situation will be -40°C < T < 125°C

Now we have to show this inequality in Fahrenheit temperature with the help of C=\frac{5}{9} (F-32)

So the compound inequality in Fahrenheit temperature will be

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7 0
2 years ago
En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0
3 years ago
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