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3 years ago

6 eggs weigh 3/4 of a pound. How much does each egg weigh?

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

8 0

$Each\: egg\: weight: \frac{3}{4} \div 6 = \frac{1}{8} \: of \: a \: pound$

steposvetlana [31]3 years ago

5 0

3/4÷6/1=?

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

3/4×1/6=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

3×1/4×6=3 2/4

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 3 and 24 using

GCF(3,24) = 3

3÷324÷3=18

Therefore:

3/4÷6/1=1/8

Solution by Formulas

Apply the fractions formula for division, to

34÷61

and solve

3×14×6

=324

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(3,24) = 3

3÷324÷3=18

Therefore:

3/4÷6/1=1/8

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Answer:

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Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$

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On which one? You did not provide anything for me to help you with.

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Answer:

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