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3 years ago

A bicycle is traveling at 20 miles per hour.

Mathematics

1 answer:

Luden [163]3 years ago

8 0

Answer:

Step-by-step explanation:

Given the conversion 1mile = 5280feet

If a bicycle is traveling at 20 miles per hour, then the bicycke must have been travelling at (20*5280)feet per hour which is equivalent to 105,600 feet per hour.

To know the number of feet that will be covered in 55seconds, we will solve the equality operation;

If 105,600 feet = 1hour (3600secs)

x foot = 55secs

where x is the amount of feet it will cover in 55 seconds?

Cross multiply

3600 * x = 105,600*55

3600x = 5,808,000

divide both sides by 3600

3600x/3600 = 5,808,000/3600

x = 1613.3 feet (to the nearest tenth)

<em>Hence the amount of feet covered in 55seconds to the nearest tenth is 1613.3 feet </em>

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$\text{Length of AB is }\frac{ah}{a+h}$

Step-by-step explanation:

Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.

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Let the side of square i.e AB is x units.

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$\frac{ND}{NP}=\frac{CD}{MP} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{AB}{PM} \\\\\frac{ND}{NP}=\frac{x}{h} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{x}{h}\\\\\frac{NP}{ND}=\frac{h}{x} \thinspace\thinspace and\thinspace\thinspace \frac{KP}{KA}=\frac{h}{x}\\\\\frac{PD}{ND}=\frac{h}{x}-1 \thinspace\thinspace and\thinspace\thinspace \frac{AP}{KA}=\frac{h}{x}-1\\$

$KA(\frac{h}{x}-1)=AP$

$ND(\frac{h}{x}-1)=PD$

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⇒ $a-x=\frac{x}{(\frac{h}{x}-1)}$

⇒ $a-x=\frac{x^2}{h-x}$

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⇒ $x=\frac{ah}{a+h}$

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