Answer:

Step-by-step explanation:
The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.
To find the
percentile for the television weights, use the formula:
, where
is the average of the set,
is some constant relevant to the percentile you're finding, and
is one standard deviation.
As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute
,
, and
:

Therefore, the 90th percentile weight is 5.1282 pounds.
Repeat the process for calculating the 10th percentile weight:

The difference between these two weights is
.
Answer: 8/17
Explanation:
2, 4, 6, 8, 10, 12, 14, 16 are all the possible even numbers from 1 through 17.
If she would use it 150 times, the expected amount would be 60 times for it to land on yellow or green
1 + 1 = 2.
2 is the answer.
I hope this helps?