Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
Answer: x= -6; y= -1
Step-by-step explanation:
-4x + y = 23
4x - 9y = - 15
-4x + y = 23
y = 23 + 4x [Add 4x to both side]
4x - 9(23 + 4x) = - 15
4x - 207 - 36x = - 15
-32x - 207 = -15
-32x = 192 [Add 207 to both side]
x = -6 [Divide -32 from both side]
-4x + y = 23
-4(-6) + y = 23 [Plug in -6 for x]
24 + y = 23 [Subtract 24 from both side]
y = -1
Answer:
6n
Step-by-step explanation:
A product refers to the multiplication of two or more numbers.
6n is the equivalent of 6*n
150 x 5= 750
20 x 5= 100 ... so they should expect 100 cellphones to be defective
