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gizmo_the_mogwai [7]
3 years ago
11

1. What is (f+g)(x)?

Mathematics
2 answers:
Alex73 [517]3 years ago
6 0

Answer:x

x^3+5x^2+16x-3

Step-by-step explanation:

KatRina [158]3 years ago
6 0

1. What is (f+g)(x)?

f(x)=8x^2+16x+6

g(x)=x^3-3x^2-9

A. x^3+5x^2+16x+3

<h2>B. x^3+8x^2+16x-3</h2>

C.x^3+5x^2+16x-3

D. 2x^3+5x^2+16x-3

i could be wrong if not B its probably A

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Answer:

3.25

Step-by-step explanation:

4 0
3 years ago
2. On a number line, G = 8 and H = –3. If H is the midpoint<br><br>of GI , find the coordinate of I.
MissTica

Answer:

-14

Step-by-step explanation:

the coordinate of I :

H = 8+I /2

-3 = 8+I /2

8+I = 2×(-3)

8+ I = -6

I = -6-8

I = -14

8 0
3 years ago
A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The
brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

  • Restaurants: We have boxes with 9 salmon each, so it will be \frac{2}{\sqrt{9}} = \frac{2}{3}
  • Grocery stores: Each carton has 49 salmon, thus the standard deviation is \frac{2}{\sqrt{49}} = \frac{2}{7}
  • Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is \frac{2}{\sqrt{64}} = \frac{1}{4}

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0
3 years ago
Four students working in a group are trying to find a rational number between
MAVERICK [17]

Answer:

d

Step-by-step explanation:

5 0
3 years ago
Look at this cone:<br><br>,,
Assoli18 [71]
  • Slant height=l=3ft
  • Radius=r=2ft

We know

\boxed{\sf \star TSA_{(Cone)}=\pi r(r+\ell)}

\\ \sf\longmapsto TSA_{(Old\:Cone)}=2 \dfrac{22}{7}\times 2(2+3)

\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{44}{7}(5)

\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{220}{7}

\\ \sf\longmapsto TSA_{(Old\:Cone)}=31.4ft^2

Now

  • New slant height =2(3)=6cm
  • New radius=2(2)=4cm

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{22}{7}\times 4(4+6)

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{88}{7}(10)

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{880}{7}

\\ \sf\longmapsto TSA_{(New\:Cone)}=125.7cm^2

So

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{125.7}{31.4}

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{4}{1}

\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cone)}}:{TSA_{(Old\:Cone)}}=4:1}}}

7 0
3 years ago
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