Using the normal distribution, it is found that 1851 people would have an IQ less than 115.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:


Z = 1
Z = 1 has a p-value of 0.8413.
Out of 2200 people:
0.8413 x 2200 = 1851.
More can be learned about the normal distribution at brainly.com/question/27643290
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I believe the answer is C
To reduce the radical, you have to factorize 108.
108 is a multiple of 3, so to factorize it, you can divide it by 3

You can rewrite the square root as:
![\sqrt[]{3\cdot36}=\sqrt[]{3}\cdot\sqrt[]{36}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%5Ccdot36%7D%3D%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D)
The square root of 36 is equal to 6 so you can write the expression as:
Answer:
452.39 mi^2
Step-by-step explanation:
A = πr^2
A = π (12mi)^2
A = 452.39 mi^2
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