Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
Answer: 1. x= -12 2. x= 12
Step-by-step explanation:
1. 5(+3)=−45
5x+15−15=−45−15
5x= -60
5x/5 = -60/5
x = -60/5
x= -12
2. 1x/2−4=2
x/2 -4=22−4+4=2+4
/2=6
2⋅2=2⋅6
x=2⋅6
x= 12
Answer:
36
Step-by-step explanation:
I got 8
because 16-8 equals 8
Answer:
You subtract 9 from both sides
Step-by-step explanation:
You have to get the variable by itself to solve so you subract 9 by 9 and they cancel each other out. Then you do -12-9 and since they are both negative you get get -21
Them you have your answer m=-21, you can check this by plugging m inot the equation
