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2 years ago

What might cause the disappearance of animals in the wild

Mathematics

2 answers:

Studentka2010 [4]2 years ago

8 0

Mainly extinction and or viruses

kondor19780726 [428]2 years ago

5 0

Viruses, food loss, water loss

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Select the property of equality used to arrive at the conclusion. if 1/3 x=5 then x=15 the multiplication property of equality t

REY [17]

If we take both sides of the equation $\frac{1}{3} x=5$ and multiply either expression by 3, the equality becomes

$3\cdot\frac{1}{3}x=3\cdot5\\x=15$

Multiplication of both sides of an equality by the same number keeps the equality true, and we call this property the multiplication property of equality.

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2 years ago

A local company employs a varying number of employees each year, based on its needs. The labor costs for the company include a f

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The answer is C
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3 years ago

HELP PLEASEE IM FAILING

aleksklad [387]

Answer:

failure is a step towards success!!

don't get urself drowned,,,,just get over it❤️

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3 years ago

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

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2 years ago

Solve the rest for me plz

Luba_88 [7]

Lo haria si pudiera que pena contigo

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2 years ago

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