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svet-max [94.6K]
3 years ago
15

A plane rises from​ take-off and flies at an angle of 9 degrees with the horizontal runway. When it has gained 500 ​feet, find t

he​ distance, to the nearest​ foot, the plane has flown. An airplane is at vertex B of a right triangle that has a horizontal side A C, a vertical side B C of length 500 feet, and a dashed hypotenuse A B of unknown length c that rises from left to right. Angle C is the right angle and angle A measures 9 degrees. 9 degrees
Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

The dashed hypotenuse measures: 3,205.13 ft.

Step-by-step explanation:

                                                               . B  (Plane is here)

                                        .                      .        

                     .                                         .      

A  .       .          .        .          .          .        . C

BC = 500 ft

Angle (Ф) between AB and AC = 9 degrees

So,

Sin(Ф) = BC/AB

Since we need to know how much hypotenuse AB measures, Let's isolate it from the equation:

AB = BC / Sin (Ф)

AB = 500 ft. / Sin (9)

AB = 500 ft./ 0.156

AB = 3,205.13 ft.

 

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What are the values of x and y?
scZoUnD [109]

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Step-by-step explanation:

In order to find the value of y, we first have to note that the unlabeled angle in the larger triangle, y and the 78 degree angle create a straight line. The unlabeled angle is equal to 36 since it and the other two angles equal 180. So we take that 36, 78 and y and can set that equal to 180.

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