Answer:
15 student
Step-by-step explanation:
35 - 21
15
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Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
40xa^2 + 24 ax + 32 a =
all you have to do is factor out a 8a from each term
aka reverse distribution property
8a (5 a + 3x + 4)
