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3 years ago

6

The perimeter of a triangle is 90 cm. The lengths of the sides of the triangle are in the ratios 3:5:7 Work out the length of th

e longest side of the triangle.

1 answer:

qwelly [4]3 years ago

7 0

Answer:

9cm 5:9

Step-by-step explanation:

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Find the area of the composite figure.

AysviL [449]

Answer:

The area will be 834.38

Step-by-step explanation:

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3 years ago

Find the equation in slope-intercept form (10,4) that is perpendicular to y=5x-3

TEA [102]

Perpendicular equation: y=-1/5x + 6

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3 years ago

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat

zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term $x^2$ , which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form $f(x)=ax^2+bx+c$ is given by the expression: $x_v=\frac{-b}{2a}$

Since in our case $a=1$ and $b=5$ , we get that the x-position of the vertex is: $x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}$

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

$y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}$

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the $x_v=-\frac{5}{2}$ . Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

$f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0$

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0

3 years ago

Which expression is equivalent to (2^5)^-2

irinina [24]

<u><em>1/1024 is the correct answer.</em></u> First you had to apply exponent rule, and it gave us, $\frac{1}{(2^5)^2}$ , or $2^5^*^2$ . Then you can also refine, and it gave us, $2^10$ , or $\frac{1}{2^10}$ . And it gave us the answer is $2^1^0=2*2*2*2*2*2*2*2*2*2=1024$ , or 1/1024 is the correct answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

4 0

3 years ago

Which number line model represents the expression -2+(-7)?<br> Khan academy help!!!!!

gtnhenbr [62]

-9 because 2+7=9 so the negative part oh then must be -9

6 0

3 years ago