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3 years ago

8

6,651,297,000 in verbal form rounded to the nearest hundred million

1 answer:

stepladder [879]3 years ago

6 0

Six billion, two hundred ninety seven million

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Please help me A.S.A.P.

Vikentia [17]

Answer:

700 Dollars

Step-by-step explanation:

The expression for solving this is I = prt

So lets start with P, that is our principal or amount of money we start with, and we want to multiply it by our rate, or r , which is 3.5, so we would do 5000 x 0.035 to get 175, then we multiply that by our time or t, which is 4 years, so 175 x 4 = 700 dollars :D

5 0

2 years ago

Read 2 more answers

What percentage is the fraction ‘2/4’ equal to ?<br> A. 30% <br> B. 20% <br> C. 50% <br> D. 40%

Solnce55 [7]

Answer: C.) 50%

Step-by-step explanation:

2/4 simplified = 1/2

1/2 = "one half"

= 50%

3 0

2 years ago

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Convert 3,124 meters to kilometers (1 kilometer =1000 meters)

Mrac [35]

Answer:

3.124 kilometers

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin

riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

$p=\frac{x}{n}$

$p=\frac{80}{100}$

$p=0.8$

Now we define hypothesis,

Null hypothesis $H_0$ : candidate A is significantly greater than 75%.

Alternative hypothesis $H_1$ : candidate A is not significantly greater than 75%.

Level of significance $\alpha=0.05$

Applying test statistic Z -proportion,

$Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where, $\widehat{p}=80\%=0.80$ and $p=75%=0.75$

Substitute the values,

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}$

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}$

$Z=\frac{0.05}{0.0433}$

$Z=1.1547$

The p-value is

$P(Z>1.1547)=1-P(Z$

$P(Z>1.1547)=1-0.8789$

$P(Z>1.1547)=0.1241$

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0

3 years ago

There are 12 cars contesting a race. The first three cars completing the race will be awarded prizes. In how many ways can the p

Sergio039 [100]

There would be 1,320 different ways, just multiply all the possible front runners 12 second runners 11 and third runners 10, 12x11x10=1,320

5 0

2 years ago