The common factors of the numbers 18 and 30 is 6
<h3>How to determine the common factors of the numbers?</h3>
The numbers are given as
18 and 30
Express 18 and 30 as a product of its factors
So, we have
18 = 2 * 3 * 3
30 = 2 * 3 * 5
Multiply the common factors in the above expression
Common factors = 2 * 3
Evaluate the product
So, we have
Common factors = 6
Hence, the common factors of the numbers 18 and 30 is 6
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Answer:
<h2>2.5 hours</h2>
Step-by-step explanation:
Step one:
given data
for train one
speed= 50miles per hour
for train two
speed= 60miles per hour
the total distance between both trains=275miles
Step two:
the expression for speed= distance/time
so that, distance= speed*time
let the time be t
we are going to combine both distances
train one distance =50t
train two distance =60t
Hence total distance
50t+60t=275
110t=1=275
t=275/110
t=2.5 hours
<u>It will take 2.5 hours</u>
(

)we need 3 equations
1. midpoint equation which is (

) when you have 2 points
2. distance formula which is D=

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height
so
x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(

)
midpoint=(

)
midpoint= (15,8)
point x=(15,8)
y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(

)
midpoint=(

)
midpoint=(13,4)
Y=(13,4)
legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D=

D=

D=

D=

D=

BC=

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D=

D=

D=

D=

D=

XY=

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=

and XY=

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D=

D=

D=

D=

D=

AD=

so we have
AD=

BC=
XY=

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(

) times 1/2 times

=
(

) times \sqrt{5} [/tex] =

=

=80

=252.982
X=(15,8)
Y=(13,4)
BC=

XY=

Area=80

square unit or 252.982 square units
You have to look at the equation and find a common factor bettween all parts. SO, we see they all have an x, so that is the first thing you can factor out. They also have
2x(5x2 4x -3) C


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