Answer:
EF , HG , Parallel
Step-by-step explanation:
Here we are given a translated quadrilateral EFGH from Quadrilateral ABCD.
Also given that AB was parallel to DC.
Now we have to fill in the certain blanks.
Here EF is parallel to AB , As EFGH is a translated image of ABCD. And EF and AB are the corresponding sides.
Also HG is parallel to DC, EFGH is a translated image of ABCD.
Also we are given that AB is parallel to DC. Hence we have following results.
AB║DC
AB║EF
Hence CD║EF
also
CD ║HG
CD║EF
Hence we can come to conclusion that
EF║HG
Hence our answer will be
corresponding segments EF and HG are parallel to each other.
We have to solve this equation:
Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:
Now we can find the roots of the quadratic polynomial as:
![\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-%28-6%29%5Cpm%5Csqrt%5B%5D%7B%28-6%29%5E2-4%5Ccdot1%5Ccdot6%7D%7D%7B2%5Ccdot1%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B36-24%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B12%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B4%5Ccdot3%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm2%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20x%3D3%5Cpm%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20x_1%3D3-%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20x_2%3D3%2B%5Csqrt%5B%5D%7B3%7D%20%5Cend%7Bgathered%7D)
Then, the solutions to the equation are:
x = 0
x = 3 - √3
x = 3 + √3
The answer to this question is 2197! Hope this helped :3
Answer:
a/30
Step-by-step explanation:
quotient means divide
a/30 because "a number" was first in the expression
Definitions of Right Angles
