I REALLY NEED HELP

1 answer:

7 0

Start by dividing both sides by -3..

-3 | x + 7| = - 12

| x + 7 | = 4 or | x + 7 | = - 4

Take out the absolute value bars

x + 7 = 4 x + 7 = -4
-7 -7 - 7 -7

x = -3 or x = -11

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Find the radius of a circle using the Pythagorean theorem, given that the center is at (1, 5) and the point (5, 1) lies on the c

Assoli18 [71]

Given :

Center of circle, C = ( 1 , 5 )

Point on circle, P = ( 5 , 1 )

To Find :

The radius of a circle.

Solution :

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Distance between two points A(p,q) and B(r,s) is given by :

$D = \sqrt{(p-r)^2+(q-s)^2}$

So, distance between the points (1, 5) and (5, 1) is :

$D = \sqrt{(1-5)^2+(5-1)^2}\\\\D = 5.66 \ units$

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4 0

2 years ago

What is the equation of the circle that has a center at (-3, 1) and a radius of 5? A) (x + 3)2 + (y - 1)2 = 5 B) (x - 3)2 + (y +

Gnoma [55]

Answer:

Step-by-step explanation:

The vertex form of the equation of a circle is $(x-h)^2 + (y-k)^2 = r^2$ where (h,k) is the center of the circle and r is the radius. This means that for the circle with center (-3,1) and radius 5 substitute into the vertex form these values. Substitute h = -3, k= 1, and r = 5. The equation becomes $(x--3)^2 + (y-1)^2 = 5^2$ . This simplifies to $(x+3)^2 + (y-1)^2 = 25$ . The solution is C.