L=w+2 and 2w+2l=44
substitute equation for length in perimeter equation
2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
w=10
substitute width into length equation to get length
l=10+2
l=12
a=lw
a=12*10
a=120 cm^2
3y = 5x + 30
y + 5x = 50 .......(1)
3y - 5x = 30 .....(2) - rearranging the first equation.
Add (1) and (2):-
4y = 80
y = 20
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30
x = 6
The 2 numbers are 6 and 20.
Roughly 24, but there's possibly like nine more. I got 24 without getting too confused
10/30 or you can symlafife
