this is how i calculated for x!
Answer:
Step-by-step explanation:
let wind velocity=x
speed of plane=y
(x+y)*4=808
x+y=808/4=202 ...(1)
(y-x)*4=488
y-x=122 ...(2)
add (1) and (2)
2y=202+122=324
y=324/2=162
from (1)
x+162=202
x=202-162=40
wind velocity=40 m/hr
speed of plane=162 m/hr
Answer:
Step-by-step explanation:
The mean SAT score is 
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it 
) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by 
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
Answer:
First figure is regular and convex.
Second figure is irregular and convex.
Step-by-step explanation:
Here given 2 polygons we have to classify these whether these are convex, concave, regular and irregular.
Regular Polygon is the polygon which have all sides and all angles equal.
Convex Polygon is the polygon in which measure of all interior angles less than 180° and if measure of each of interior angle greater than 180° then it is concave.
In the first figure, all sides are equal therefore and each of interior angle of polygon is less than 180°. Hence, the polygon is regular and convex.
In the second figure, all sides are not equal and each of interior angle of polygon is less than 180°. Hence, the polygon is irregular and convex.
