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3 years ago

Find the slope of the line that passes through (-2,-3) and (1,1).

2 answers:

8 0

Slope formula : (y2 - y1) / (x2 - x1)
(-2,-3)...x1 = -2 and y1 = -3
(1,1)...x2 = 1 and y2 = 1
time to sub and solve
slope = (1 - (-2) / (1 - (-3) = (1 + 2) / (1 + 3) = 3/4 <==

Svet_ta [14]3 years ago

3 0

Answer: 4/3

Step-by-step explanation:

(-2,-3) x'= -2 y'= -3

(1,1) x"=1 y"=1

slope. (x'-x")= y'-y"

slope. (-2-1)=-3-1

slope. -3 = -4

slope = 4/3

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Slav-nsk [51]

Answer:

Step-by-step explanation:

Let's find the area of each of the two circles.

First Circle:

The first circle has a diameter of 10 inches. That means the radius is 5 inches. So, its area is:

$A=\pi r^2\\A=\pi (5)^2\\A=25\pi$

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The second circle has a diameter twice that of the first. So, the diameter is 20 inches. This means that the radius is 10 inches. Find the area:

$A=\pi r^2\\A=\pi (10)^2\\A=100\pi$

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3 years ago

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3 years ago

Help and explain explain !!!!!!!!!!

tigry1 [53]

Answer:

$x=-1\text{ or }x=11$

Step-by-step explanation:

For $a=|b|$ , we have two cases:

$\begin{cases}a=b,\\a=-b\end{cases}$

Therefore, for $18=|15-3x|$ , we have the following cases:

$\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}$

Solving, we have:

$\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}$ .

Therefore,

$\implies \boxed{x=-1\text{ or }x=11}$

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3 years ago