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sineoko [7]
3 years ago
10

I need help with another set of math questions.

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).

For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.

Rinse and repeat question 12 for question 13
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PLEASE HELP ASAP!!<br> Rewrite the expression with a rational exponent as a radical expression.
allochka39001 [22]

Answer:

D)-  3√5^4

Your answer is D^

8 0
3 years ago
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Please help 15 points each but beware if you use my points for no reason I'll report you
romanna [79]

Answer:

2048~ \text{in}^3

Step-by-step explanation:

\text{Volume,}~ V = \dfrac 43 \pi r^3 \\\\\\~~~~~~~~~~~~~~~=\dfrac 43 \times 3 \times 8^3\\\\\\~~~~~~~~~~~~~~~=4 \times 512\\\\\\~~~~~~~~~~~~~~~=2048~ \text{in}^3

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Find the derivative of f(x) = 4x + 7 at x = 5.(2 points)
Sveta_85 [38]

Answer:

x=4x+7=

x=5=

Step-by-step explanation:

5 0
3 years ago
Among all right circular cones with a slant height of 24​, what are the dimensions​ (radius and​ height) that maximize the volum
aleksklad [387]

Answer:

5571.99

Step-by-step explanation:

We need to use the Pythagorean theorem to solve the problem.

The theorem indicates that,

r^2+h^2=24^2 \\r^2+h^2=576\\r^2=576-h^2

Once this is defined, we proceed to define the volume of a cone,

v=\frac{1}{3}\pi r^2 h

Substituting,

v=\frac{1}{3} \pi (576-h^2)h\\v=\frac{1}{3} \pi (576h-h^3)

We need to find the maximum height, so we proceed to calculate h, by means of its derivative and equalizing 0,

\frac{dv}{dh} = \frac{1}{3} \pi (576-3h^2)

\frac{dv}{dh} = 0 then \rightarrow \frac{1}{3}\pi(576-3h^2)=0

h_1=-8\sqrt{3}\\h_2=8\sqrt{3}

<em>We select the positiv value.</em>

We have then,

r^2 = 576-(8\sqrt3)^2 = 384\\r=\sqrt{384}

We can now calculate the maximum volume,

V_{max}= \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (\sqrt{384})^2 (8\sqrt{3}) = 5571.99

4 0
3 years ago
Find the surface area of cube whose volume is 64 cm cube
Oksana_A [137]
V = L³ = 64 => L = ∛64 = 4 cm

A = L² = 4² = 16 cm²

At = 16 x 6 = 96 cm²
3 0
3 years ago
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