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Alina [70]
3 years ago
10

Which equations are true?

Mathematics
2 answers:
bija089 [108]3 years ago
8 0

Answer:

B is correct

Step-by-step explanation:

-(-x) = x, because a double negative like this equals a positive.

Therefore, you are actually saying -x+x= 0 which is true.

azamat3 years ago
3 0

Equation B. is true for all values of x.

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What is the median of 137 115 104 to 63 and 98
Romashka-Z-Leto [24]

Answer:

104

Step-by-step explanation:

put them from  less to highest  then find the middle number

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3 years ago
Michael took in 91 mile bike trip. he left home at 7 AM. If he stopped for a total of two hours for rest and food and averaged 1
Korvikt [17]
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5 0
3 years ago
150=2x do the work out please​
IrinaVladis [17]

Answer:

Let's solve the expression!

Step-by-step explanation:

150 = 2x

\frac{150}{2}=\frac{2x}{2}

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I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
7 0
3 years ago
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What is the answer to f-7/g= h for f
gtnhenbr [62]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s
Ierofanga [76]

Option B:

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$\beta=10\log\left(\frac{I}{I_0} \right)

where I_0=1\times10^{-12}\ \text {watts}/ \text m^2}

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

10^{12}

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$10^{12}=\left(\frac{I}{I_0} \right)

$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)

Now, do the cross multiplication,

I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{0} \ \text {watts}/ \text m^2}

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Option B is the correct answer.

Hence I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}.

5 0
3 years ago
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