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Sqrt 11 is approximately 3.31662479036
So make a line from about -5 to 5 and just estimate where that could be, between the numbers 3 and 4, make sure you mark that that is sqrt 11
Answer:

Step-by-step explanation:
So first calculate what fraction of the circumference the arc is.

Now the circumference is 6, so one eighteenth of that is 
Answer:
729 square units
Step-by-step explanation:
If the width of the square is 27, then the length is also 27. After all, this is a square with four equal sides.
The area of a square is A = s^2, where s is the length of one side.
Here, A = 27^2 = 729 square units.
The answer for this question is
11/3