Answer:
A∩B=∅
Step-by-step explanation:
A intersect B have no elements in common - so we have the empty set.
Answer:
Step-by-step explanation:
the polynomial function is; (x - i)(x-2)(x+2)
Answer:
-12, -3, 5, 9
Step-by-step explanation:
ok. So the numbers are 5, -3, -12, and 9.
In these numbers, there are 2 negatives. They are -12 and -3.
In negatives, the bigger the number is, the number is smaller.
So we first put
-12, -3 as our 2 first. Then the other ones are 5 and 9.
and you obviously know that 5 is less than 9. try it out. 9-5 =4 which is positive
So then you put 5, 9
And our full answer is
-12, -3, 5, 9
X = height of pole (in meters)
With respect to the 50 degree angle, the side x is the opposite leg. It is the leg furthest from the reference angle. The hypotenuse is 5 meters.
The trig function sine ties together the opposite and hypotenuse
sin(angle) = opposite/hypotenuse
sin(50) = x/5
5*sin(50) = x .... multiply both sides by 5
x = 5*sin(50)
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Since x = 5*sin(50) isn't listed as an answer choice, let's try using cosine. We can't use it right away because we don't know the adjacent side. What we can do is change the reference angle. The missing angle of the triangle is 90-50 = 40 degrees. Let's make the 40 degree angle the reference angle
So x is now the adjacent side with respect to the 40 degree reference angle. The hypotenuse is always the longest side. The hypotenuse stays at 5.
cos(angle) = adjacent/hypotenuse
cos(40) = x/5
5*cos(40) = x
x = 5*cos(40)
This expression is listed. The answer is choice B
Answer:
The option which is used to inscribe a square in a circle is option B
B. Construct a perpendicular bisector of the diameter of the circle
Step-by-step explanation:
The steps required to inscribe a square in a circle are;
1) Draw the circle using a compass
2) Draw the diameter of the circle, that passes through the center of the circle with a straight edge label the endpoint of the diameter X and Y
3) Construct the line perpendicular to the diameter of the circle and label the endpoints as A and B
The figure formed by joining the endpoints X, Y, A, and B is the inscribed square of the circle
Therefore, the correct option is to construct a perpendicular bisector of the diameter of the circle.
