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3 years ago

Help plz someone help me plz ty

Mathematics

1 answer:

MrRa [10]3 years ago

7 0

Answer: 18.75 for each girl

Step-by-step explanation:

First you take the unit rate 2.50 multiply by 5.

2.50 x 5 = 12.50

12.50 x 3 = 37.50

37.50 / 2 = 18.75

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after the interview ,Ellen decided to hire two of the applicants and reject the others .Ellen's assistant called back the applic

Elden [556K]

Answer:

40 + 2r

Step-by-step explanation:

Well an hour has 60 minutes.

So 60 x 1/30 = 60/30 = 2 minutes for each person that didn't get into the job

60 x 1/3 = 60/3 = 20 minutes for the people that made it into the job.

20 x 2 = 40 minutes in total for the people that made it into the job.

We don't know how much people got rejected so:

The answer is

40 + 2r

7 0

2 years ago

Which of the following expressions could be interpreted as "a number times negative seven added to five equals two"?

masha68 [24]

Answer:

5-7 x = 2

Step-by-step explanation:

a number times negative seven added to five equals two

7 0

3 years ago

Read 2 more answers

PLEASE HELP DUE IN 1 HOUR

kobusy [5.1K]

Choosing blue or red: 3 blue + 4 red = 7 marbles
3 blue + 2 green + 4 red + 1 yellow = 10 marbles

Probability blue or red marble: 7/10

Choosing a marble that isn't blue or red: 2 green + 1 yellow = 3 marbles
Total marbles: 3 blue + 2 green + 4 red + 1 yellow = 10 marbles

Probability non-blue or red marble: 3/10

5 0

3 years ago

Can someone help me with (d)

zysi [14]

Answer:

Step-by-step explanation:

1 to the power of anything is still one

1 * 1 * 1 * 1 = 1

8 0

3 years ago

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago