Since we aren't told the length of the 3rd bar, focus solely on the lengths of the first 2 bars. Add together their lengths: 1.15 cm + 3.92 cm = 5.07 cm.
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
x = 3 ± 
Step-by-step explanation:
x² - 6x - 4 = 0 ( add 4 to both sides )
x² - 6x = 4
To complete the square
add ( half the coefficient of the x- term)² to both sides
x² + 2(- 3)x + 9 = 4 + 9
(x - 3)² = 13 ( take square root of both sides )
x - 3 = ± ( add 3 to both sides )
x = 3 ±
The angle is going to be a 65° angle
